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121044402251 = 975111241341
BaseRepresentation
bin111000010111011001…
…1110000000001001011
3102120102210101202001022
41300232303300001023
53440344331333001
6131335041343055
711513410304633
oct1605663600113
9376383352038
10121044402251
1147375455a83
121b561637a8b
13b55069ca76
145c03d316c3
153236a0811b
hex1c2ecf004b

121044402251 has 4 divisors (see below), whose sum is σ = 121045741104. Its totient is φ = 121043063400.

The previous prime is 121044402233. The next prime is 121044402263. The reversal of 121044402251 is 152204440121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121044402251 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 121044402251.

It is not an unprimeable number, because it can be changed into a prime (121044402751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523160 + ... + 718181.

It is an arithmetic number, because the mean of its divisors is an integer number (30261435276).

Almost surely, 2121044402251 is an apocalyptic number.

121044402251 is a deficient number, since it is larger than the sum of its proper divisors (1338853).

121044402251 is an equidigital number, since it uses as much as digits as its factorization.

121044402251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1338852.

The product of its (nonzero) digits is 2560, while the sum is 26.

Adding to 121044402251 its reverse (152204440121), we get a palindrome (273248842372).

The spelling of 121044402251 in words is "one hundred twenty-one billion, forty-four million, four hundred two thousand, two hundred fifty-one".

Divisors: 1 97511 1241341 121044402251