Base | Representation |
---|---|
bin | 1011000000111001010011… |
… | …1010101100000010001001 |
3 | 1120212201001111121010020222 |
4 | 2300032110322230002021 |
5 | 3041402300333020410 |
6 | 41431132400155425 |
7 | 2356630236653441 |
oct | 260162472540211 |
9 | 46781044533228 |
10 | 12110011220105 |
11 | 3949910698827 |
12 | 1437002308b75 |
13 | 69ac7a3177b6 |
14 | 2dc1b0483121 |
15 | 160020ed2955 |
hex | b0394eac089 |
12110011220105 has 8 divisors (see below), whose sum is σ = 14533524283200. Its totient is φ = 9687001763376.
The previous prime is 12110011220051. The next prime is 12110011220143. The reversal of 12110011220105 is 50102211001121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12110011220105 - 210 = 12110011219081 is a prime.
It is a super-2 number, since 2×121100112201052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125848685 + ... + 125944874.
It is an arithmetic number, because the mean of its divisors is an integer number (1816690535400).
Almost surely, 212110011220105 is an apocalyptic number.
It is an amenable number.
12110011220105 is a deficient number, since it is larger than the sum of its proper divisors (2423513063095).
12110011220105 is an equidigital number, since it uses as much as digits as its factorization.
12110011220105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 251803183.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 12110011220105 its reverse (50102211001121), we get a palindrome (62212222221226).
The spelling of 12110011220105 in words is "twelve trillion, one hundred ten billion, eleven million, two hundred twenty thousand, one hundred five".
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