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12110012022003 = 375471054236269
BaseRepresentation
bin1011000000111001010011…
…1101101111110011110011
31120212201001120002212020220
42300032110331233303303
53041402301034201003
641431132425304123
72356630246533360
oct260162475576363
946781046085226
1012110012022003
113949911096255
121437002635043
1369ac7a5387ac
142dc1b0611467
151600210e0353
hexb0394f6fcf3

12110012022003 has 16 divisors (see below), whose sum is σ = 18487087230720. Its totient is φ = 6907356027936.

The previous prime is 12110012021999. The next prime is 12110012022023. The reversal of 12110012022003 is 30022021001121.

It is not a de Polignac number, because 12110012022003 - 22 = 12110012021999 is a prime.

It is a super-2 number, since 2×121100120220032 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12110012022023) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 527106648 + ... + 527129621.

It is an arithmetic number, because the mean of its divisors is an integer number (1155442951920).

Almost surely, 212110012022003 is an apocalyptic number.

12110012022003 is a deficient number, since it is larger than the sum of its proper divisors (6377075208717).

12110012022003 is a wasteful number, since it uses less digits than its factorization.

12110012022003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1054236826.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12110012022003 its reverse (30022021001121), we get a palindrome (42132033023124).

The spelling of 12110012022003 in words is "twelve trillion, one hundred ten billion, twelve million, twenty-two thousand, three".

Divisors: 1 3 7 21 547 1641 3829 11487 1054236269 3162708807 7379653883 22138961649 576667239143 1730001717429 4036670674001 12110012022003