12110114433 has 4 divisors (see below), whose sum is σ = 16146819248. Its totient is φ = 8073409620.

The previous prime is 12110114347. The next prime is 12110114449. The reversal of 12110114433 is 33441101121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33441101121 = 3 ⋅11147033707.

It is not a de Polignac number, because 12110114433 - 2¹⁸ = 12109852289 is a prime.

It is a super-2 number, since 2×12110114433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12110114473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018352403 + ... + 2018352408.

It is an arithmetic number, because the mean of its divisors is an integer number (4036704812).

Almost surely, 2^12110114433 is an apocalyptic number.

It is an amenable number.

12110114433 is a deficient number, since it is larger than the sum of its proper divisors (4036704815).

12110114433 is an equidigital number, since it uses as much as digits as its factorization.

12110114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4036704814.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 12110114433 its reverse (33441101121), we get a palindrome (45551215554).

The spelling of 12110114433 in words is "twelve billion, one hundred ten million, one hundred fourteen thousand, four hundred thirty-three".