121102130122033 has 4 divisors (see below), whose sum is σ = 121645189001728. Its totient is φ = 120559071242340.

The previous prime is 121102130121989. The next prime is 121102130122049. The reversal of 121102130122033 is 330221031201121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121102130122033 - 2¹³ = 121102130113841 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121102130121995 and 121102130122013.

It is not an unprimeable number, because it can be changed into a prime (121102130123033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271529439513 + ... + 271529439958.

It is an arithmetic number, because the mean of its divisors is an integer number (30411297250432).

Almost surely, 2^{121102130122033} is an apocalyptic number.

It is an amenable number.

121102130122033 is a deficient number, since it is larger than the sum of its proper divisors (543058879695).

121102130122033 is an equidigital number, since it uses as much as digits as its factorization.

121102130122033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 543058879694.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 121102130122033 its reverse (330221031201121), we get a palindrome (451323161323154).

The spelling of 121102130122033 in words is "one hundred twenty-one trillion, one hundred two billion, one hundred thirty million, one hundred twenty-two thousand, thirty-three".