12110303113121 has 4 divisors (see below), whose sum is σ = 12135170265792. Its totient is φ = 12085435960452.

The previous prime is 12110303113081. The next prime is 12110303113159. The reversal of 12110303113121 is 12131130301121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12110303113121 - 2²⁶ = 12110236004257 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12110303113093 and 12110303113102.

It is not an unprimeable number, because it can be changed into a prime (12110303113721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12433575605 + ... + 12433576578.

It is an arithmetic number, because the mean of its divisors is an integer number (3033792566448).

Almost surely, 2^{12110303113121} is an apocalyptic number.

It is an amenable number.

12110303113121 is a deficient number, since it is larger than the sum of its proper divisors (24867152671).

12110303113121 is an equidigital number, since it uses as much as digits as its factorization.

12110303113121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24867152670.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 12110303113121 its reverse (12131130301121), we get a palindrome (24241433414242).

The spelling of 12110303113121 in words is "twelve trillion, one hundred ten billion, three hundred three million, one hundred thirteen thousand, one hundred twenty-one".