1211031311113 has 4 divisors (see below), whose sum is σ = 1304187565828. Its totient is φ = 1117875056400.

The previous prime is 1211031311089. The next prime is 1211031311123. The reversal of 1211031311113 is 3111131301121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 782310177289 + 428721133824 = 884483^2 + 654768^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211031311113 - 2⁵ = 1211031311081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1211031311123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46578127338 + ... + 46578127363.

It is an arithmetic number, because the mean of its divisors is an integer number (326046891457).

Almost surely, 2^{1211031311113} is an apocalyptic number.

1211031311113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1211031311113 is a deficient number, since it is larger than the sum of its proper divisors (93156254715).

1211031311113 is an equidigital number, since it uses as much as digits as its factorization.

1211031311113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93156254714.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1211031311113 its reverse (3111131301121), we get a palindrome (4322162612234).

The spelling of 1211031311113 in words is "one trillion, two hundred eleven billion, thirty-one million, three hundred eleven thousand, one hundred thirteen".