12110422433 has 4 divisors (see below), whose sum is σ = 12392060208. Its totient is φ = 11828784660.

The previous prime is 12110422427. The next prime is 12110422469. The reversal of 12110422433 is 33422401121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33422401121 = 61363 ⋅544667.

It is a cyclic number.

It is not a de Polignac number, because 12110422433 - 2¹⁰ = 12110421409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12110422399 and 12110422408.

It is not an unprimeable number, because it can be changed into a prime (12110422033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140818823 + ... + 140818908.

It is an arithmetic number, because the mean of its divisors is an integer number (3098015052).

Almost surely, 2^12110422433 is an apocalyptic number.

It is an amenable number.

12110422433 is a deficient number, since it is larger than the sum of its proper divisors (281637775).

12110422433 is an equidigital number, since it uses as much as digits as its factorization.

12110422433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 281637774.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12110422433 its reverse (33422401121), we get a palindrome (45532823554).

The spelling of 12110422433 in words is "twelve billion, one hundred ten million, four hundred twenty-two thousand, four hundred thirty-three".