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1211050153 = 1931962687
BaseRepresentation
bin100100000101111…
…0010100010101001
310010101210201111101
41020023302202221
54440012101103
6320101001401
742003520315
oct11013624251
93111721441
101211050153
115716739a5
122996b3261
13163b93031
14b6ba8b45
15714bea1d
hex482f28a9

1211050153 has 4 divisors (see below), whose sum is σ = 1211132160. Its totient is φ = 1210968148.

The previous prime is 1211050133. The next prime is 1211050187. The reversal of 1211050153 is 3510501121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3510501121 = 5959500019.

It is a cyclic number.

It is not a de Polignac number, because 1211050153 - 29 = 1211049641 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1211050153.

It is not an unprimeable number, because it can be changed into a prime (1211050133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12025 + ... + 50662.

It is an arithmetic number, because the mean of its divisors is an integer number (302783040).

Almost surely, 21211050153 is an apocalyptic number.

It is an amenable number.

1211050153 is a deficient number, since it is larger than the sum of its proper divisors (82007).

1211050153 is an equidigital number, since it uses as much as digits as its factorization.

1211050153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82006.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 1211050153 is about 34800.1458761310. The cubic root of 1211050153 is about 1065.9104245913.

Adding to 1211050153 its reverse (3510501121), we get a palindrome (4721551274).

The spelling of 1211050153 in words is "one billion, two hundred eleven million, fifty thousand, one hundred fifty-three".

Divisors: 1 19319 62687 1211050153