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1211052113 = 5920526307
BaseRepresentation
bin100100000101111…
…0011000001010001
310010101210211011222
41020023303001101
54440012131423
6320101014425
742003526115
oct11013630121
93111724158
101211052113
11571675417
122996b4415
13163b93bab
14b6ba9745
15714c03c8
hex482f3051

1211052113 has 4 divisors (see below), whose sum is σ = 1231578480. Its totient is φ = 1190525748.

The previous prime is 1211052109. The next prime is 1211052119. The reversal of 1211052113 is 3112501121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211052113 - 22 = 1211052109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1211052091 and 1211052100.

It is not an unprimeable number, because it can be changed into a prime (1211052119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10263095 + ... + 10263212.

It is an arithmetic number, because the mean of its divisors is an integer number (307894620).

Almost surely, 21211052113 is an apocalyptic number.

It is an amenable number.

1211052113 is a deficient number, since it is larger than the sum of its proper divisors (20526367).

1211052113 is an equidigital number, since it uses as much as digits as its factorization.

1211052113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20526366.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 1211052113 is about 34800.1740369211. The cubic root of 1211052113 is about 1065.9109996249.

Adding to 1211052113 its reverse (3112501121), we get a palindrome (4323553234).

The spelling of 1211052113 in words is "one billion, two hundred eleven million, fifty-two thousand, one hundred thirteen".

Divisors: 1 59 20526307 1211052113