1211114143403 has 4 divisors (see below), whose sum is σ = 1211118224568. Its totient is φ = 1211110062240.

The previous prime is 1211114143399. The next prime is 1211114143441. The reversal of 1211114143403 is 3043414111121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1211114143403 - 2² = 1211114143399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1211114103403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1557293 + ... + 2201678.

It is an arithmetic number, because the mean of its divisors is an integer number (302779556142).

Almost surely, 2^{1211114143403} is an apocalyptic number.

1211114143403 is a deficient number, since it is larger than the sum of its proper divisors (4081165).

1211114143403 is an equidigital number, since it uses as much as digits as its factorization.

1211114143403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4081164.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 1211114143403 its reverse (3043414111121), we get a palindrome (4254528254524).

The spelling of 1211114143403 in words is "one trillion, two hundred eleven billion, one hundred fourteen million, one hundred forty-three thousand, four hundred three".