Base | Representation |
---|---|
bin | 10001100111111100111… |
… | …110101100001010000011 |
3 | 11021210010201221220011101 |
4 | 101213330332230022003 |
5 | 124320343301234103 |
6 | 2324215133155231 |
7 | 153333635004124 |
oct | 21477476541203 |
9 | 4253121856141 |
10 | 1211130102403 |
11 | 427701406831 |
12 | 17688502bb17 |
13 | 8a294465610 |
14 | 428947c404b |
15 | 21786dc8a1d |
hex | 119fcfac283 |
1211130102403 has 16 divisors (see below), whose sum is σ = 1309761246976. Its totient is φ = 1113284684160.
The previous prime is 1211130102379. The next prime is 1211130102467. The reversal of 1211130102403 is 3042010311121.
It is a cyclic number.
It is not a de Polignac number, because 1211130102403 - 221 = 1211128005251 is a prime.
It is a super-2 number, since 2×12111301024032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1211130102493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6172750 + ... + 6365932.
It is an arithmetic number, because the mean of its divisors is an integer number (81860077936).
Almost surely, 21211130102403 is an apocalyptic number.
1211130102403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1211130102403 is a deficient number, since it is larger than the sum of its proper divisors (98631144573).
1211130102403 is a wasteful number, since it uses less digits than its factorization.
1211130102403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195214.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1211130102403 its reverse (3042010311121), we get a palindrome (4253140413524).
The spelling of 1211130102403 in words is "one trillion, two hundred eleven billion, one hundred thirty million, one hundred two thousand, four hundred three".
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