12111313133033 has 4 divisors (see below), whose sum is σ = 12637891964928. Its totient is φ = 11584734301140.

The previous prime is 12111313133011. The next prime is 12111313133047. The reversal of 12111313133033 is 33033131311121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12111313133033 - 2⁶ = 12111313132969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12111313132993 and 12111313133011.

It is not an unprimeable number, because it can be changed into a prime (12111313133333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263289415913 + ... + 263289415958.

It is an arithmetic number, because the mean of its divisors is an integer number (3159472991232).

Almost surely, 2^{12111313133033} is an apocalyptic number.

It is an amenable number.

12111313133033 is a deficient number, since it is larger than the sum of its proper divisors (526578831895).

12111313133033 is an equidigital number, since it uses as much as digits as its factorization.

12111313133033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 526578831894.

The product of its (nonzero) digits is 1458, while the sum is 26.

Adding to 12111313133033 its reverse (33033131311121), we get a palindrome (45144444444154).

The spelling of 12111313133033 in words is "twelve trillion, one hundred eleven billion, three hundred thirteen million, one hundred thirty-three thousand, thirty-three".