12111313330441 has 4 divisors (see below), whose sum is σ = 13042952817412. Its totient is φ = 11179673843472.

The previous prime is 12111313330429. The next prime is 12111313330489. The reversal of 12111313330441 is 14403331311121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4006786876416 + 8104526454025 = 2001696^2 + 2846845^2 .

It is a cyclic number.

It is not a de Polignac number, because 12111313330441 - 2⁷ = 12111313330313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12111313330241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465819743466 + ... + 465819743491.

It is an arithmetic number, because the mean of its divisors is an integer number (3260738204353).

Almost surely, 2^{12111313330441} is an apocalyptic number.

It is an amenable number.

12111313330441 is a deficient number, since it is larger than the sum of its proper divisors (931639486971).

12111313330441 is an equidigital number, since it uses as much as digits as its factorization.

12111313330441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 931639486970.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 12111313330441 its reverse (14403331311121), we get a palindrome (26514644641562).

The spelling of 12111313330441 in words is "twelve trillion, one hundred eleven billion, three hundred thirteen million, three hundred thirty thousand, four hundred forty-one".