12111320033 has 4 divisors (see below), whose sum is σ = 12502007808. Its totient is φ = 11720632260.

The previous prime is 12111320027. The next prime is 12111320041. The reversal of 12111320033 is 33002311121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12111320033 - 2¹⁶ = 12111254497 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12111319993 and 12111320020.

It is not an unprimeable number, because it can be changed into a prime (12111320003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195343841 + ... + 195343902.

It is an arithmetic number, because the mean of its divisors is an integer number (3125501952).

Almost surely, 2^12111320033 is an apocalyptic number.

It is an amenable number.

12111320033 is a deficient number, since it is larger than the sum of its proper divisors (390687775).

12111320033 is an equidigital number, since it uses as much as digits as its factorization.

12111320033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 390687774.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 12111320033 its reverse (33002311121), we get a palindrome (45113631154).

The spelling of 12111320033 in words is "twelve billion, one hundred eleven million, three hundred twenty thousand, thirty-three".