Base | Representation |
---|---|
bin | 10001100111111101000… |
… | …101111110001100101011 |
3 | 11021210010212112212200112 |
4 | 101213331011332030223 |
5 | 124320344243330212 |
6 | 2324215242124535 |
7 | 153333660144341 |
oct | 21477505761453 |
9 | 4253125485615 |
10 | 1211132011307 |
11 | 42770249aa39 |
12 | 1768857b074b |
13 | 8a29498344a |
14 | 42894b5d991 |
15 | 21787154422 |
hex | 119fd17e32b |
1211132011307 has 4 divisors (see below), whose sum is σ = 1211395133880. Its totient is φ = 1210868888736.
The previous prime is 1211132011301. The next prime is 1211132011319. The reversal of 1211132011307 is 7031102311121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211132011307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1211132011301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131554382 + ... + 131563587.
It is an arithmetic number, because the mean of its divisors is an integer number (302848783470).
Almost surely, 21211132011307 is an apocalyptic number.
1211132011307 is a deficient number, since it is larger than the sum of its proper divisors (263122573).
1211132011307 is an equidigital number, since it uses as much as digits as its factorization.
1211132011307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 263122572.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 1211132011307 its reverse (7031102311121), we get a palindrome (8242234322428).
The spelling of 1211132011307 in words is "one trillion, two hundred eleven billion, one hundred thirty-two million, eleven thousand, three hundred seven".
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