Base | Representation |
---|---|
bin | 111000011001011101… |
… | …0010001011110001011 |
3 | 102120121120220002121222 |
4 | 1300302322101132023 |
5 | 3441014441033003 |
6 | 131345540352255 |
7 | 11515204251455 |
oct | 1606272213613 |
9 | 376546802558 |
10 | 121113221003 |
11 | 4740028a585 |
12 | 1b5806a568b |
13 | b561a16a18 |
14 | 5c0d1272d5 |
15 | 323ca9dc38 |
hex | 1c32e9178b |
121113221003 has 4 divisors (see below), whose sum is σ = 121123772328. Its totient is φ = 121102669680.
The previous prime is 121113220999. The next prime is 121113221011. The reversal of 121113221003 is 300122311121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300122311121 = 20807 ⋅14424103.
It is a cyclic number.
It is not a de Polignac number, because 121113221003 - 22 = 121113220999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121113221903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5258426 + ... + 5281407.
It is an arithmetic number, because the mean of its divisors is an integer number (30280943082).
Almost surely, 2121113221003 is an apocalyptic number.
121113221003 is a deficient number, since it is larger than the sum of its proper divisors (10551325).
121113221003 is a wasteful number, since it uses less digits than its factorization.
121113221003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10551324.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 121113221003 its reverse (300122311121), we get a palindrome (421235532124).
The spelling of 121113221003 in words is "one hundred twenty-one billion, one hundred thirteen million, two hundred twenty-one thousand, three".
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