12111430433 has 8 divisors (see below), whose sum is σ = 12830080320. Its totient is φ = 11400901200.

The previous prime is 12111430361. The next prime is 12111430451. The reversal of 12111430433 is 33403411121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12111430433 - 2³⁰ = 11037688609 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12111430399 and 12111430408.

It is not an unprimeable number, because it can be changed into a prime (12111430493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2027093 + ... + 2033058.

It is an arithmetic number, because the mean of its divisors is an integer number (1603760040).

Almost surely, 2^12111430433 is an apocalyptic number.

It is an amenable number.

12111430433 is a deficient number, since it is larger than the sum of its proper divisors (718649887).

12111430433 is a wasteful number, since it uses less digits than its factorization.

12111430433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4060327.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 12111430433 its reverse (33403411121), we get a palindrome (45514841554).

The spelling of 12111430433 in words is "twelve billion, one hundred eleven million, four hundred thirty thousand, four hundred thirty-three".