1211201111131 has 4 divisors (see below), whose sum is σ = 1321310303064. Its totient is φ = 1101091919200.

The previous prime is 1211201111117. The next prime is 1211201111147. The reversal of 1211201111131 is 1311111021121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1211201111131 - 2¹³ = 1211201102939 is a prime.

It is a super-2 number, since 2×1211201111131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1211201111101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55054595950 + ... + 55054595971.

It is an arithmetic number, because the mean of its divisors is an integer number (330327575766).

Almost surely, 2^{1211201111131} is an apocalyptic number.

1211201111131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1211201111131 is a deficient number, since it is larger than the sum of its proper divisors (110109191933).

1211201111131 is a wasteful number, since it uses less digits than its factorization.

1211201111131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110109191932.

The product of its (nonzero) digits is 12, while the sum is 16.

Adding to 1211201111131 its reverse (1311111021121), we get a palindrome (2522312132252).

The spelling of 1211201111131 in words is "one trillion, two hundred eleven billion, two hundred one million, one hundred eleven thousand, one hundred thirty-one".