1211202241113 has 4 divisors (see below), whose sum is σ = 1614936321488. Its totient is φ = 807468160740.

The previous prime is 1211202241027. The next prime is 1211202241199. The reversal of 1211202241113 is 3111422021121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1211202241027) and next prime (1211202241199).

It is not a de Polignac number, because 1211202241113 - 2¹⁰ = 1211202240089 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1211202241113.

It is not an unprimeable number, because it can be changed into a prime (1211202141113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201867040183 + ... + 201867040188.

It is an arithmetic number, because the mean of its divisors is an integer number (403734080372).

Almost surely, 2^{1211202241113} is an apocalyptic number.

It is an amenable number.

1211202241113 is a deficient number, since it is larger than the sum of its proper divisors (403734080375).

1211202241113 is an equidigital number, since it uses as much as digits as its factorization.

1211202241113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 403734080374.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 1211202241113 its reverse (3111422021121), we get a palindrome (4322624262234).

The spelling of 1211202241113 in words is "one trillion, two hundred eleven billion, two hundred two million, two hundred forty-one thousand, one hundred thirteen".