12112122130033 has 4 divisors (see below), whose sum is σ = 12749602242160. Its totient is φ = 11474642017908.

The previous prime is 12112122129979. The next prime is 12112122130039. The reversal of 12112122130033 is 33003122121121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12112122130033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12112122129986 and 12112122130013.

It is not an unprimeable number, because it can be changed into a prime (12112122130039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318740056035 + ... + 318740056072.

It is an arithmetic number, because the mean of its divisors is an integer number (3187400560540).

Almost surely, 2^{12112122130033} is an apocalyptic number.

It is an amenable number.

12112122130033 is a deficient number, since it is larger than the sum of its proper divisors (637480112127).

12112122130033 is an equidigital number, since it uses as much as digits as its factorization.

12112122130033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 637480112126.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 12112122130033 its reverse (33003122121121), we get a palindrome (45115244251154).

The spelling of 12112122130033 in words is "twelve trillion, one hundred twelve billion, one hundred twenty-two million, one hundred thirty thousand, thirty-three".