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12112130003 = 75771598539
BaseRepresentation
bin10110100011111000…
…00110111111010011
31011021010002221210112
423101330012333103
5144301201130003
65321512551535
7606102256241
oct132174067723
934233087715
1012112130003
115155a885a6
1224203b25ab
1311b046453c
1482c889791
154ad51e3d8
hex2d1f06fd3

12112130003 has 4 divisors (see below), whose sum is σ = 12113736120. Its totient is φ = 12110523888.

The previous prime is 12112129973. The next prime is 12112130021. The reversal of 12112130003 is 30003121121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12112130003 - 220 = 12111081427 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12112130003.

It is not an unprimeable number, because it can be changed into a prime (12112130083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 791693 + ... + 806846.

It is an arithmetic number, because the mean of its divisors is an integer number (3028434030).

Almost surely, 212112130003 is an apocalyptic number.

12112130003 is a deficient number, since it is larger than the sum of its proper divisors (1606117).

12112130003 is an equidigital number, since it uses as much as digits as its factorization.

12112130003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1606116.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 12112130003 its reverse (30003121121), we get a palindrome (42115251124).

It can be divided in two parts, 121121 and 30003, that multiplied together give a palindrome (3633993363).

The spelling of 12112130003 in words is "twelve billion, one hundred twelve million, one hundred thirty thousand, three".

Divisors: 1 7577 1598539 12112130003