12112211100121 has 4 divisors (see below), whose sum is σ = 13213321200144. Its totient is φ = 11011101000100.

The previous prime is 12112211100043. The next prime is 12112211100139. The reversal of 12112211100121 is 12100111221121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12112211100121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12112211100095 and 12112211100104.

It is not an unprimeable number, because it can be changed into a prime (12112211104121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550555049995 + ... + 550555050016.

It is an arithmetic number, because the mean of its divisors is an integer number (3303330300036).

Almost surely, 2^{12112211100121} is an apocalyptic number.

12112211100121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12112211100121 is a deficient number, since it is larger than the sum of its proper divisors (1101110100023).

12112211100121 is a wasteful number, since it uses less digits than its factorization.

12112211100121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1101110100022.

The product of its (nonzero) digits is 16, while the sum is 16.

Adding to 12112211100121 its reverse (12100111221121), we get a palindrome (24212322321242).

The spelling of 12112211100121 in words is "twelve trillion, one hundred twelve billion, two hundred eleven million, one hundred thousand, one hundred twenty-one".