Base | Representation |
---|---|
bin | 1011000001000010001101… |
… | …1110101011101010010001 |
3 | 1120212221020012012011111022 |
4 | 2300100203132223222101 |
5 | 3041422200133123213 |
6 | 41432210000525225 |
7 | 2360043431636312 |
oct | 260204336535221 |
9 | 46787205164438 |
10 | 12112403020433 |
11 | 394a92880a811 |
12 | 143756b320815 |
13 | 69b26b9c2171 |
14 | 2dc359daa609 |
15 | 160110e89308 |
hex | b04237aba91 |
12112403020433 has 8 divisors (see below), whose sum is σ = 12407933341440. Its totient is φ = 11816877740320.
The previous prime is 12112403020427. The next prime is 12112403020453. The reversal of 12112403020433 is 33402030421121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12112403020433 - 214 = 12112403004049 is a prime.
It is a super-2 number, since 2×121124030204332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12112403020453) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3854216 + ... + 6251382.
It is an arithmetic number, because the mean of its divisors is an integer number (1550991667680).
Almost surely, 212112403020433 is an apocalyptic number.
It is an amenable number.
12112403020433 is a deficient number, since it is larger than the sum of its proper divisors (295530321007).
12112403020433 is a wasteful number, since it uses less digits than its factorization.
12112403020433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2520447.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 12112403020433 its reverse (33402030421121), we get a palindrome (45514433441554).
The spelling of 12112403020433 in words is "twelve trillion, one hundred twelve billion, four hundred three million, twenty thousand, four hundred thirty-three".
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