12113004009 has 4 divisors (see below), whose sum is σ = 16150672016. Its totient is φ = 8075336004.

The previous prime is 12113003989. The next prime is 12113004011. The reversal of 12113004009 is 90040031121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12113004009 - 2⁸ = 12113003753 is a prime.

It is a super-2 number, since 2×12113004009² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12113004109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018833999 + ... + 2018834004.

It is an arithmetic number, because the mean of its divisors is an integer number (4037668004).

Almost surely, 2^12113004009 is an apocalyptic number.

It is an amenable number.

12113004009 is a deficient number, since it is larger than the sum of its proper divisors (4037668007).

12113004009 is an equidigital number, since it uses as much as digits as its factorization.

12113004009 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4037668006.

The product of its (nonzero) digits is 216, while the sum is 21.

The spelling of 12113004009 in words is "twelve billion, one hundred thirteen million, four thousand, nine".