12113023400041 has 4 divisors (see below), whose sum is σ = 12155825603152. Its totient is φ = 12070221196932.

The previous prime is 12113023400021. The next prime is 12113023400111. The reversal of 12113023400041 is 14000432031121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12113023400041 - 2¹⁵ = 12113023367273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12113023399985 and 12113023400021.

It is not an unprimeable number, because it can be changed into a prime (12113023400021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21401101131 + ... + 21401101696.

It is an arithmetic number, because the mean of its divisors is an integer number (3038956400788).

Almost surely, 2^{12113023400041} is an apocalyptic number.

It is an amenable number.

12113023400041 is a deficient number, since it is larger than the sum of its proper divisors (42802203111).

12113023400041 is an equidigital number, since it uses as much as digits as its factorization.

12113023400041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42802203110.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12113023400041 its reverse (14000432031121), we get a palindrome (26113455431162).

The spelling of 12113023400041 in words is "twelve trillion, one hundred thirteen billion, twenty-three million, four hundred thousand, forty-one".