121132110113 has 16 divisors (see below), whose sum is σ = 142927724544. Its totient is φ = 100460440080.

The previous prime is 121132110107. The next prime is 121132110139. The reversal of 121132110113 is 311011231121.

It is not a de Polignac number, because 121132110113 - 2¹⁰ = 121132109089 is a prime.

It is a super-3 number, since 3×121132110113³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121132110091 and 121132110100.

It is not an unprimeable number, because it can be changed into a prime (121132110413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1257056 + ... + 1349982.

It is an arithmetic number, because the mean of its divisors is an integer number (8932982784).

Almost surely, 2^121132110113 is an apocalyptic number.

It is an amenable number.

121132110113 is a deficient number, since it is larger than the sum of its proper divisors (21795614431).

121132110113 is an equidigital number, since it uses as much as digits as its factorization.

121132110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98972.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 121132110113 its reverse (311011231121), we get a palindrome (432143341234).

The spelling of 121132110113 in words is "one hundred twenty-one billion, one hundred thirty-two million, one hundred ten thousand, one hundred thirteen".