121132111111113 has 4 divisors (see below), whose sum is σ = 161509481481488. Its totient is φ = 80754740740740.

The previous prime is 121132111111093. The next prime is 121132111111199. The reversal of 121132111111113 is 311111111231121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 121132111111113 - 2¹² = 121132111107017 is a prime.

It is a super-2 number, since 2×121132111111113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 121132111111113.

It is not an unprimeable number, because it can be changed into a prime (121132111111313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20188685185183 + ... + 20188685185188.

It is an arithmetic number, because the mean of its divisors is an integer number (40377370370372).

Almost surely, 2^{121132111111113} is an apocalyptic number.

It is an amenable number.

121132111111113 is a deficient number, since it is larger than the sum of its proper divisors (40377370370375).

121132111111113 is an equidigital number, since it uses as much as digits as its factorization.

121132111111113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40377370370374.

The product of its digits is 36, while the sum is 21.

Adding to 121132111111113 its reverse (311111111231121), we get a palindrome (432243222342234).

The spelling of 121132111111113 in words is "one hundred twenty-one trillion, one hundred thirty-two billion, one hundred eleven million, one hundred eleven thousand, one hundred thirteen".