12113221003 has 4 divisors (see below), whose sum is σ = 13045007248. Its totient is φ = 11181434760.

The previous prime is 12113220991. The next prime is 12113221019. The reversal of 12113221003 is 30012231121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12113221003 - 2⁵ = 12113220971 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12113221063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465893103 + ... + 465893128.

It is an arithmetic number, because the mean of its divisors is an integer number (3261251812).

Almost surely, 2^12113221003 is an apocalyptic number.

12113221003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12113221003 is a deficient number, since it is larger than the sum of its proper divisors (931786245).

12113221003 is an equidigital number, since it uses as much as digits as its factorization.

12113221003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 931786244.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12113221003 its reverse (30012231121), we get a palindrome (42125452124).

The spelling of 12113221003 in words is "twelve billion, one hundred thirteen million, two hundred twenty-one thousand, three".