Search a number
-
+
12113300113 = 13788418249
BaseRepresentation
bin10110100100000001…
…00100101010010001
31011021012022101212221
423102000210222101
5144302001100423
65321554021041
7606115231525
oct132200445221
934235271787
1012113300113
115156707732
122420877781
1311b0784005
1482cab1d85
154ad6a0e5d
hex2d2024a91

12113300113 has 4 divisors (see below), whose sum is σ = 12201718500. Its totient is φ = 12024881728.

The previous prime is 12113300057. The next prime is 12113300141. The reversal of 12113300113 is 31100331121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4800826944 + 7312473169 = 69288^2 + 85513^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12113300113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12113300153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44208988 + ... + 44209261.

It is an arithmetic number, because the mean of its divisors is an integer number (3050429625).

Almost surely, 212113300113 is an apocalyptic number.

It is an amenable number.

12113300113 is a deficient number, since it is larger than the sum of its proper divisors (88418387).

12113300113 is an equidigital number, since it uses as much as digits as its factorization.

12113300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88418386.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 12113300113 its reverse (31100331121), we get a palindrome (43213631234).

The spelling of 12113300113 in words is "twelve billion, one hundred thirteen million, three hundred thousand, one hundred thirteen".

Divisors: 1 137 88418249 12113300113