12113303131 has 4 divisors (see below), whose sum is σ = 12825850392. Its totient is φ = 11400755872.

The previous prime is 12113303101. The next prime is 12113303173. The reversal of 12113303131 is 13130331121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12113303131 - 2⁵ = 12113303099 is a prime.

It is a super-2 number, since 2×12113303131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12113303099 and 12113303108.

It is not an unprimeable number, because it can be changed into a prime (12113303101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356273605 + ... + 356273638.

It is an arithmetic number, because the mean of its divisors is an integer number (3206462598).

Almost surely, 2^12113303131 is an apocalyptic number.

12113303131 is a deficient number, since it is larger than the sum of its proper divisors (712547261).

12113303131 is an equidigital number, since it uses as much as digits as its factorization.

12113303131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 712547260.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 12113303131 its reverse (13130331121), we get a palindrome (25243634252).

It can be divided in two parts, 1211330 and 3131, that added together give a triangular number (1214461 = T₁₅₅₈).

The spelling of 12113303131 in words is "twelve billion, one hundred thirteen million, three hundred three thousand, one hundred thirty-one".