Base | Representation |
---|---|
bin | 10001101000001000111… |
… | …101110110111111000001 |
3 | 11021210122202101021120101 |
4 | 101220020331312333001 |
5 | 124321301242224301 |
6 | 2324251115442401 |
7 | 153341626260136 |
oct | 21501075667701 |
9 | 4253582337511 |
10 | 1211331211201 |
11 | 4277a4986851 |
12 | 176920456401 |
13 | 8a2c701a4c7 |
14 | 428b33b458d |
15 | 217998a1701 |
hex | 11a08f76fc1 |
1211331211201 has 4 divisors (see below), whose sum is σ = 1211486061312. Its totient is φ = 1211176361092.
The previous prime is 1211331211141. The next prime is 1211331211213. The reversal of 1211331211201 is 1021121331121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1211331211201 - 215 = 1211331178433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1211331211271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77413321 + ... + 77428966.
It is an arithmetic number, because the mean of its divisors is an integer number (302871515328).
Almost surely, 21211331211201 is an apocalyptic number.
It is an amenable number.
1211331211201 is a deficient number, since it is larger than the sum of its proper divisors (154850111).
1211331211201 is an equidigital number, since it uses as much as digits as its factorization.
1211331211201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 154850110.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1211331211201 its reverse (1021121331121), we get a palindrome (2232452542322).
The spelling of 1211331211201 in words is "one trillion, two hundred eleven billion, three hundred thirty-one million, two hundred eleven thousand, two hundred one".
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