12113341131 has 4 divisors (see below), whose sum is σ = 16151121512. Its totient is φ = 8075560752.

The previous prime is 12113341129. The next prime is 12113341147. The reversal of 12113341131 is 13114331121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13114331121 = 3 ⋅4371443707.

It is not a de Polignac number, because 12113341131 - 2¹ = 12113341129 is a prime.

It is a super-2 number, since 2×12113341131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12113341098 and 12113341107.

It is not an unprimeable number, because it can be changed into a prime (12113341931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018890186 + ... + 2018890191.

It is an arithmetic number, because the mean of its divisors is an integer number (4037780378).

Almost surely, 2^12113341131 is an apocalyptic number.

12113341131 is a deficient number, since it is larger than the sum of its proper divisors (4037780381).

12113341131 is an equidigital number, since it uses as much as digits as its factorization.

12113341131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4037780380.

The product of its digits is 216, while the sum is 21.

Adding to 12113341131 its reverse (13114331121), we get a palindrome (25227672252).

The spelling of 12113341131 in words is "twelve billion, one hundred thirteen million, three hundred forty-one thousand, one hundred thirty-one".