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12113400323 = 84191438817
BaseRepresentation
bin10110100100000001…
…11101001000000011
31011021012111111100102
423102000331020003
5144302012302243
65322000113015
7606116126633
oct132200751003
934235444312
1012113400323
115156775a52
12242090576b
1311b07ba7cb
1482cada6c3
154ad6c09b8
hex2d203d203

12113400323 has 4 divisors (see below), whose sum is σ = 12114847560. Its totient is φ = 12111953088.

The previous prime is 12113400307. The next prime is 12113400331. The reversal of 12113400323 is 32300431121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12113400323 - 24 = 12113400307 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12113400295 and 12113400304.

It is not an unprimeable number, because it can be changed into a prime (12113400023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 710990 + ... + 727827.

It is an arithmetic number, because the mean of its divisors is an integer number (3028711890).

Almost surely, 212113400323 is an apocalyptic number.

12113400323 is a deficient number, since it is larger than the sum of its proper divisors (1447237).

12113400323 is an equidigital number, since it uses as much as digits as its factorization.

12113400323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1447236.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 12113400323 its reverse (32300431121), we get a palindrome (44413831444).

The spelling of 12113400323 in words is "twelve billion, one hundred thirteen million, four hundred thousand, three hundred twenty-three".

Divisors: 1 8419 1438817 12113400323