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121134042003 = 31325693120889
BaseRepresentation
bin111000011010000100…
…1101100101110010011
3102120200001001220200010
41300310021230232103
53441040303321003
6131352002530003
711515546240212
oct1606411545623
9376601056603
10121134042003
1147411010717
121b587666903
13b566126a40
145c11bc7079
15323e813003
hex1c3426cb93

121134042003 has 16 divisors (see below), whose sum is σ = 173944268960. Its totient is φ = 74540507904.

The previous prime is 121134041969. The next prime is 121134042013. The reversal of 121134042003 is 300240431121.

It is not a de Polignac number, because 121134042003 - 29 = 121134041491 is a prime.

It is a super-2 number, since 2×1211340420032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121134042013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 941583 + ... + 1062471.

It is an arithmetic number, because the mean of its divisors is an integer number (10871516810).

Almost surely, 2121134042003 is an apocalyptic number.

121134042003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

121134042003 is a deficient number, since it is larger than the sum of its proper divisors (52810226957).

121134042003 is a wasteful number, since it uses less digits than its factorization.

121134042003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146598.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 121134042003 its reverse (300240431121), we get a palindrome (421374473124).

The spelling of 121134042003 in words is "one hundred twenty-one billion, one hundred thirty-four million, forty-two thousand, three".

Divisors: 1 3 13 39 25693 77079 120889 334009 362667 1002027 1571557 4714671 3106001077 9318003231 40378014001 121134042003