121134211325131 has 4 divisors (see below), whose sum is σ = 121135219494192. Its totient is φ = 121133203156072.

The previous prime is 121134211325093. The next prime is 121134211325161. The reversal of 121134211325131 is 131523112431121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121134211325131 - 2¹³ = 121134211316939 is a prime.

It is a super-2 number, since 2×121134211325131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121134211325093 and 121134211325102.

It is not an unprimeable number, because it can be changed into a prime (121134211325161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503904280 + ... + 504144613.

It is an arithmetic number, because the mean of its divisors is an integer number (30283804873548).

Almost surely, 2^{121134211325131} is an apocalyptic number.

121134211325131 is a deficient number, since it is larger than the sum of its proper divisors (1008169061).

121134211325131 is a wasteful number, since it uses less digits than its factorization.

121134211325131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1008169060.

The product of its digits is 4320, while the sum is 31.

Adding to 121134211325131 its reverse (131523112431121), we get a palindrome (252657323756252).

The spelling of 121134211325131 in words is "one hundred twenty-one trillion, one hundred thirty-four billion, two hundred eleven million, three hundred twenty-five thousand, one hundred thirty-one".