121140131044331 has 8 divisors (see below), whose sum is σ = 139055757726720. Its totient is φ = 103376977780968.

The previous prime is 121140131044319. The next prime is 121140131044397. The reversal of 121140131044331 is 133440131041121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121140131044331 - 2¹⁴ = 121140131027947 is a prime.

It is a super-3 number, since 3×121140131044331³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121140131044294 and 121140131044303.

It is not an unprimeable number, because it can be changed into a prime (121140131044301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38118353051 + ... + 38118356228.

It is an arithmetic number, because the mean of its divisors is an integer number (17381969715840).

Almost surely, 2^{121140131044331} is an apocalyptic number.

121140131044331 is a deficient number, since it is larger than the sum of its proper divisors (17915626682389).

121140131044331 is an equidigital number, since it uses as much as digits as its factorization.

121140131044331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76236709513.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 121140131044331 its reverse (133440131041121), we get a palindrome (254580262085452).

The spelling of 121140131044331 in words is "one hundred twenty-one trillion, one hundred forty billion, one hundred thirty-one million, forty-four thousand, three hundred thirty-one".