121140320331 has 4 divisors (see below), whose sum is σ = 161520427112. Its totient is φ = 80760213552.

The previous prime is 121140320321. The next prime is 121140320359. The reversal of 121140320331 is 133023041121.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 121140320331 - 2¹⁸ = 121140058187 is a prime.

It is a super-4 number, since 4×121140320331⁴ (a number of 45 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3, 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121140320298 and 121140320307.

It is not an unprimeable number, because it can be changed into a prime (121140320321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20190053386 + ... + 20190053391.

It is an arithmetic number, because the mean of its divisors is an integer number (40380106778).

Almost surely, 2^121140320331 is an apocalyptic number.

121140320331 is a deficient number, since it is larger than the sum of its proper divisors (40380106781).

121140320331 is an equidigital number, since it uses as much as digits as its factorization.

121140320331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40380106780.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 121140320331 its reverse (133023041121), we get a palindrome (254163361452).

The spelling of 121140320331 in words is "one hundred twenty-one billion, one hundred forty million, three hundred twenty thousand, three hundred thirty-one".