12114234203 has 4 divisors (see below), whose sum is σ = 12131321280. Its totient is φ = 12097147128.

The previous prime is 12114234193. The next prime is 12114234233. The reversal of 12114234203 is 30243241121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12114234203 is a prime.

It is a super-3 number, since 3×12114234203³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12114234233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8542475 + ... + 8543892.

It is an arithmetic number, because the mean of its divisors is an integer number (3032830320).

Almost surely, 2^12114234203 is an apocalyptic number.

12114234203 is a deficient number, since it is larger than the sum of its proper divisors (17087077).

12114234203 is an equidigital number, since it uses as much as digits as its factorization.

12114234203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17087076.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12114234203 its reverse (30243241121), we get a palindrome (42357475324).

The spelling of 12114234203 in words is "twelve billion, one hundred fourteen million, two hundred thirty-four thousand, two hundred three".