12114300403 has 8 divisors (see below), whose sum is σ = 12145518000. Its totient is φ = 12083124480.

The previous prime is 12114300389. The next prime is 12114300409. The reversal of 12114300403 is 30400341121.

12114300403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12114300403 - 2⁵ = 12114300371 is a prime.

It is a super-3 number, since 3×12114300403³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12114300409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 619723 + ... + 638971.

It is an arithmetic number, because the mean of its divisors is an integer number (1518189750).

Almost surely, 2^12114300403 is an apocalyptic number.

12114300403 is a deficient number, since it is larger than the sum of its proper divisors (31217597).

12114300403 is an equidigital number, since it uses as much as digits as its factorization.

12114300403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20837.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 12114300403 its reverse (30400341121), we get a palindrome (42514641524).

The spelling of 12114300403 in words is "twelve billion, one hundred fourteen million, three hundred thousand, four hundred three".