1211430044003 has 4 divisors (see below), whose sum is σ = 1239602835768. Its totient is φ = 1183257252240.

The previous prime is 1211430043987. The next prime is 1211430044047. The reversal of 1211430044003 is 3004400341121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1211430044003 - 2⁴ = 1211430043987 is a prime.

It is a super-3 number, since 3×1211430044003³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1211430044003.

It is not an unprimeable number, because it can be changed into a prime (1211430044053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14086395818 + ... + 14086395903.

It is an arithmetic number, because the mean of its divisors is an integer number (309900708942).

Almost surely, 2^{1211430044003} is an apocalyptic number.

1211430044003 is a deficient number, since it is larger than the sum of its proper divisors (28172791765).

1211430044003 is an equidigital number, since it uses as much as digits as its factorization.

1211430044003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28172791764.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1211430044003 its reverse (3004400341121), we get a palindrome (4215830385124).

The spelling of 1211430044003 in words is "one trillion, two hundred eleven billion, four hundred thirty million, forty-four thousand, three".