Base | Representation |
---|---|
bin | 1011000001001001100110… |
… | …1011010101000101111001 |
3 | 1120220010100101121101000210 |
4 | 2300102121223111011321 |
5 | 3041440230312003403 |
6 | 41433134440021333 |
7 | 2360143531250022 |
oct | 260223153250571 |
9 | 46803311541023 |
10 | 12114386047353 |
11 | 3950756114237 |
12 | 1437a23461849 |
13 | 69b4c67a5a85 |
14 | 2dc4a74c7c49 |
15 | 1601ca0e7b03 |
hex | b0499ad5179 |
12114386047353 has 4 divisors (see below), whose sum is σ = 16152514729808. Its totient is φ = 8076257364900.
The previous prime is 12114386047289. The next prime is 12114386047363. The reversal of 12114386047353 is 35374068341121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12114386047353 - 26 = 12114386047289 is a prime.
It is a super-3 number, since 3×121143860473533 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12114386047363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2019064341223 + ... + 2019064341228.
It is an arithmetic number, because the mean of its divisors is an integer number (4038128682452).
Almost surely, 212114386047353 is an apocalyptic number.
It is an amenable number.
12114386047353 is a deficient number, since it is larger than the sum of its proper divisors (4038128682455).
12114386047353 is an equidigital number, since it uses as much as digits as its factorization.
12114386047353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4038128682454.
The product of its (nonzero) digits is 1451520, while the sum is 48.
The spelling of 12114386047353 in words is "twelve trillion, one hundred fourteen billion, three hundred eighty-six million, forty-seven thousand, three hundred fifty-three".
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