12114402532523 has 4 divisors (see below), whose sum is σ = 12114992090400. Its totient is φ = 12113812974648.

The previous prime is 12114402532489. The next prime is 12114402532553. The reversal of 12114402532523 is 32523520441121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12114402532523 - 2⁴⁰ = 11014890904747 is a prime.

It is a super-3 number, since 3×12114402532523³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12114402532553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294748115 + ... + 294789212.

It is an arithmetic number, because the mean of its divisors is an integer number (3028748022600).

Almost surely, 2^{12114402532523} is an apocalyptic number.

12114402532523 is a deficient number, since it is larger than the sum of its proper divisors (589557877).

12114402532523 is an equidigital number, since it uses as much as digits as its factorization.

12114402532523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 589557876.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 12114402532523 its reverse (32523520441121), we get a palindrome (44637922973644).

The spelling of 12114402532523 in words is "twelve trillion, one hundred fourteen billion, four hundred two million, five hundred thirty-two thousand, five hundred twenty-three".