12114410313 has 4 divisors (see below), whose sum is σ = 16152547088. Its totient is φ = 8076273540.

The previous prime is 12114410303. The next prime is 12114410359. The reversal of 12114410313 is 31301441121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31301441121 = 3 ⋅10433813707.

It is not a de Polignac number, because 12114410313 - 2⁵ = 12114410281 is a prime.

It is a super-3 number, since 3×12114410313³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12114410313.

It is not an unprimeable number, because it can be changed into a prime (12114410303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2019068383 + ... + 2019068388.

It is an arithmetic number, because the mean of its divisors is an integer number (4038136772).

Almost surely, 2^12114410313 is an apocalyptic number.

It is an amenable number.

12114410313 is a deficient number, since it is larger than the sum of its proper divisors (4038136775).

12114410313 is an equidigital number, since it uses as much as digits as its factorization.

12114410313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4038136774.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 12114410313 its reverse (31301441121), we get a palindrome (43415851434).

The spelling of 12114410313 in words is "twelve billion, one hundred fourteen million, four hundred ten thousand, three hundred thirteen".