Base | Representation |
---|---|
bin | 111000011010011000… |
… | …0001100010110001001 |
3 | 102120200202001120220210 |
4 | 1300310300030112021 |
5 | 3441100344224001 |
6 | 131353003111333 |
7 | 11516031066063 |
oct | 1606460142611 |
9 | 376622046823 |
10 | 121144133001 |
11 | 47416783191 |
12 | 1b58ab12549 |
13 | b56824ab48 |
14 | 5c13292733 |
15 | 3240657dd6 |
hex | 1c34c0c589 |
121144133001 has 4 divisors (see below), whose sum is σ = 161525510672. Its totient is φ = 80762755332.
The previous prime is 121144132999. The next prime is 121144133021. The reversal of 121144133001 is 100331441121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 121144133001 - 21 = 121144132999 is a prime.
It is a super-3 number, since 3×1211441330013 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121144133021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20190688831 + ... + 20190688836.
It is an arithmetic number, because the mean of its divisors is an integer number (40381377668).
Almost surely, 2121144133001 is an apocalyptic number.
It is an amenable number.
121144133001 is a deficient number, since it is larger than the sum of its proper divisors (40381377671).
121144133001 is an equidigital number, since it uses as much as digits as its factorization.
121144133001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40381377670.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 121144133001 its reverse (100331441121), we get a palindrome (221475574122).
The spelling of 121144133001 in words is "one hundred twenty-one billion, one hundred forty-four million, one hundred thirty-three thousand, one".
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