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12115115 = 52423023
BaseRepresentation
bin101110001101…
…110010101011
3211210111210222
4232031302223
511100140430
61111400255
7204656015
oct56156253
924714728
1012115115
1169252a1
12408308b
13268250c
1418751b5
1510e49e5
hexb8dcab

12115115 has 4 divisors (see below), whose sum is σ = 14538144. Its totient is φ = 9692088.

The previous prime is 12115091. The next prime is 12115123. The reversal of 12115115 is 51151121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51151121 = 77307303.

It is a cyclic number.

It is not a de Polignac number, because 12115115 - 212 = 12111019 is a prime.

It is a super-2 number, since 2×121151152 = 293552022926450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12115093 and 12115102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1211507 + ... + 1211516.

It is an arithmetic number, because the mean of its divisors is an integer number (3634536).

Almost surely, 212115115 is an apocalyptic number.

12115115 is a deficient number, since it is larger than the sum of its proper divisors (2423029).

12115115 is an equidigital number, since it uses as much as digits as its factorization.

12115115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2423028.

The product of its digits is 50, while the sum is 17.

The square root of 12115115 is about 3480.6773766036. The cubic root of 12115115 is about 229.6725965464.

Adding to 12115115 its reverse (51151121), we get a palindrome (63266236).

The spelling of 12115115 in words is "twelve million, one hundred fifteen thousand, one hundred fifteen".

Divisors: 1 5 2423023 12115115