Base | Representation |
---|---|
bin | 10110100100110100… |
… | …10000000001001011 |
3 | 1011021122222101100102 |
4 | 23102122100001023 |
5 | 144310212000212 |
6 | 5322354200015 |
7 | 606226365146 |
oct | 132232200113 |
9 | 34248871312 |
10 | 12120031307 |
11 | 515a4949aa |
12 | 2422b8300b |
13 | 11b1c9ca77 |
14 | 82d94505d |
15 | 4ae0805c2 |
hex | 2d269004b |
12120031307 has 4 divisors (see below), whose sum is σ = 12120455016. Its totient is φ = 12119607600.
The previous prime is 12120031283. The next prime is 12120031349. The reversal of 12120031307 is 70313002121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70313002121 = 1283 ⋅54803587.
It is a cyclic number.
It is not a de Polignac number, because 12120031307 - 210 = 12120030283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12120036307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165578 + ... + 227279.
It is an arithmetic number, because the mean of its divisors is an integer number (3030113754).
Almost surely, 212120031307 is an apocalyptic number.
12120031307 is a deficient number, since it is larger than the sum of its proper divisors (423709).
12120031307 is an equidigital number, since it uses as much as digits as its factorization.
12120031307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 423708.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 12120031307 its reverse (70313002121), we get a palindrome (82433033428).
The spelling of 12120031307 in words is "twelve billion, one hundred twenty million, thirty-one thousand, three hundred seven".
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