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121201331411 = 177129490083
BaseRepresentation
bin111000011100000101…
…0011000110011010011
3102120211201200120101102
41300320022120303103
53441210020101121
6131402405055015
711520324214226
oct1607012306323
9376751616342
10121201331411
1147445aa01a6
121b5a60b746b
13b577056864
145c1ab015bd
1532456a590b
hex1c38298cd3

121201331411 has 4 divisors (see below), whose sum is σ = 128330821512. Its totient is φ = 114071841312.

The previous prime is 121201331401. The next prime is 121201331429. The reversal of 121201331411 is 114133102121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121201331411 - 210 = 121201330387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121201331401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3564745025 + ... + 3564745058.

It is an arithmetic number, because the mean of its divisors is an integer number (32082705378).

Almost surely, 2121201331411 is an apocalyptic number.

121201331411 is a deficient number, since it is larger than the sum of its proper divisors (7129490101).

121201331411 is an equidigital number, since it uses as much as digits as its factorization.

121201331411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7129490100.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 121201331411 its reverse (114133102121), we get a palindrome (235334433532).

The spelling of 121201331411 in words is "one hundred twenty-one billion, two hundred one million, three hundred thirty-one thousand, four hundred eleven".

Divisors: 1 17 7129490083 121201331411