121201510454041 has 4 divisors (see below), whose sum is σ = 122073463766800. Its totient is φ = 120329557141284.

The previous prime is 121201510454033. The next prime is 121201510454047. The reversal of 121201510454041 is 140454015102121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121201510454041 - 2³ = 121201510454033 is a prime.

It is a super-2 number, since 2×121201510454041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121201510453994 and 121201510454012.

It is not an unprimeable number, because it can be changed into a prime (121201510454047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435976656171 + ... + 435976656448.

It is an arithmetic number, because the mean of its divisors is an integer number (30518365941700).

Almost surely, 2^{121201510454041} is an apocalyptic number.

It is an amenable number.

121201510454041 is a deficient number, since it is larger than the sum of its proper divisors (871953312759).

121201510454041 is an equidigital number, since it uses as much as digits as its factorization.

121201510454041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 871953312758.

The product of its (nonzero) digits is 6400, while the sum is 31.

Adding to 121201510454041 its reverse (140454015102121), we get a palindrome (261655525556162).

The spelling of 121201510454041 in words is "one hundred twenty-one trillion, two hundred one billion, five hundred ten million, four hundred fifty-four thousand, forty-one".