Base | Representation |
---|---|
bin | 10001101000111100110… |
… | …000110011001101111011 |
3 | 11021212220022112122101200 |
4 | 101220330300303031323 |
5 | 124330041223000011 |
6 | 2324513241145243 |
7 | 153402310501251 |
oct | 21507460631573 |
9 | 4255808478350 |
10 | 1212200203131 |
11 | 42810045a2a5 |
12 | 176b2348b223 |
13 | 8a405078108 |
14 | 4295697c5d1 |
15 | 217ead05856 |
hex | 11a3cc3337b |
1212200203131 has 12 divisors (see below), whose sum is σ = 1757931771960. Its totient is φ = 804913812000.
The previous prime is 1212200203121. The next prime is 1212200203139. The reversal of 1212200203131 is 1313020022121.
It is not a de Polignac number, because 1212200203131 - 217 = 1212200072059 is a prime.
It is a super-2 number, since 2×12122002031312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1212200203139) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 268302346 + ... + 268306863.
It is an arithmetic number, because the mean of its divisors is an integer number (146494314330).
Almost surely, 21212200203131 is an apocalyptic number.
1212200203131 is a deficient number, since it is larger than the sum of its proper divisors (545731568829).
1212200203131 is a wasteful number, since it uses less digits than its factorization.
1212200203131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 536609466 (or 536609463 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1212200203131 its reverse (1313020022121), we get a palindrome (2525220225252).
The spelling of 1212200203131 in words is "one trillion, two hundred twelve billion, two hundred million, two hundred three thousand, one hundred thirty-one".
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